xisu Posted March 11, 2020 Share #1 Posted March 11, 2020 Math problems? Call 1-800-[(10x)(13i)^2]-[sin(xy)/2.362x]. 3 Link to comment
SuperModerator BamSec1 Posted March 27, 2020 SuperModerator Share #2 Posted March 27, 2020 In order for [(10x)(13i)^2)] to be between 100 and 999 inclusive, we need x to be between -16.9 and -1.691691692. But then the expression [sin(xy)/2.362x] has a maximum value of 0.250264293. Also, the last part must be a four digit integer ... it must be 0000, but real phone numbers don't use 0000 as the last four digits. That is, assuming that sin(xy)/2.362x means sin(xy)/(2.362x). If it means x sin(xy) / 2.362, then the last four digits could also be 0000 to 0007. And if we allow y to be a complex number, then the last four digits could be any four-digit integer. That's what I read somewhere. 2 Link to comment
Administrator Bad Karma Posted March 28, 2020 Administrator Share #3 Posted March 28, 2020 Too brainy for me to stay focused 1 Link to comment
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